WAEC 2019 PHYSICS PRACTICAL SOLUTION
WAEC 2019 PHYSICS PRACTICAL SOLUTION
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PHYSICS PRACTICAL SOLUTION BY EXAMKING DITTO
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(1aviii)
In a tabular form
Under y(cm)
20.0, 30.0, 40.0, 50.0, 60.0
Under t(s)
36.61, 33.66, 31.32, 28.62, 25.93
Under T = t/20(s)
1.8305, 1.6830, 1.5660, 1.4310, 1.2965
Under T²(s²)
3.3507, 2.8325, 2.4524, 2.0478, 1.6809
(1ax)
Slope s = ΔT²/Δy
S = 4 - 2.5/0 - 39
S = 1.5/-39
S = -0.0385
Intercept, C = 4.0
(1axi)
SR = c
R = c/s = 4/-0.0385 = -103.9
(1axii)
(i) I ensured that the retort stand was well clamped.
(ii) I avoided error due to parallax when reading the metre rule.
In a tabular form
Under y(cm)
20.0, 30.0, 40.0, 50.0, 60.0
Under t(s)
36.61, 33.66, 31.32, 28.62, 25.93
Under T = t/20(s)
1.8305, 1.6830, 1.5660, 1.4310, 1.2965
Under T²(s²)
3.3507, 2.8325, 2.4524, 2.0478, 1.6809
(1ax)
Slope s = ΔT²/Δy
S = 4 - 2.5/0 - 39
S = 1.5/-39
S = -0.0385
Intercept, C = 4.0
(1axi)
SR = c
R = c/s = 4/-0.0385 = -103.9
(1axii)
(i) I ensured that the retort stand was well clamped.
(ii) I avoided error due to parallax when reading the metre rule.
(1bi)
Draw the diagram
(α) K.E is maximum
(β) acceleration is maximum
(1bii)
Period, T = 2π√m/k
Given : weight, W = 120N
Mass = w/g = 120/10 = 12
T = 45
π = 3.142
4 = 2(3.142)√12/k
0.6365 = √12/k
Square both sides
0.405 = 12
K = 12/0.405 = 29.6
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Draw the diagram
(α) K.E is maximum
(β) acceleration is maximum
(1bii)
Period, T = 2π√m/k
Given : weight, W = 120N
Mass = w/g = 120/10 = 12
T = 45
π = 3.142
4 = 2(3.142)√12/k
0.6365 = √12/k
Square both sides
0.405 = 12
K = 12/0.405 = 29.6
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E.m.f, E = 3.00v
(3avii)
In a tabular form
Under R(ohms)
2.0, 5.0, 10.0, 12.0, 15.0, 20.0
Under V(v)
0.86, 0.62, 0.43, 0.38, 0.32, 0.25
Under V-¹(v-¹)
1.1628, 1.6129, 2.3256, 2.6316, 3.1250, 4.0000
(3aix)
Slope s = ΔR/Δv-¹
=17.5 - 4.25/3.5 - 1.5
=13.25/2
=6.625
Intercept, C = -5.75
(3ax)
S = Roα
6.625 = 0.85(α)
α = 6.625/0.85 = 7.79
C = -(Ro + β)
= -5.75 = -(0.85 + β)
β = 5.75 - 0.85
β = 4.9
(3axi)
(i) I ensured tight connections.
(ii) I avoided error due to parallax when reading the voltmeter.
(3bi)
Vab = 12 - 8 = 4v
Rab = 4×5/4+5 = 20/9ohms
Iab = Vab/Rab = 4/20/9 = 4 ×9/20 = 9/5
=1.8A
Power = I²ab Rab
=1.8² * 20/9
= 7.2watts
(3bii)
Current in line = power/voltage = 3600/240
=15A
Circuit breaker remain closed because current in line is less than 20A
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IMAGES SOLUTIONS FOR ALL QUESTIONS.
*PHYSICS PRACTICALS PRECAUTIONS*✍🏾
*_✅TAKE NOTE ALL PRECAUTIONS DROPPED_*
Precautions (Electricity) N.B-Always past tense.
1. I ensured that electric terminals were tightly connected to avoid partial contact .
2. I ensured that the key was open when the readings were not taken in oder to avoid running down the cell or battery.
3. I avoided parallax error of the voltmeter when taking my reading.
4. I ensured that i avoided zero error of the voltmeter when taking my reading.
5. I ensured that i used short connecting wires to minimize the resistance of the lengthy wire and conserve the energy of the battery. Ohms law ; V∞I I.e V=IR (T & OPA constant )
Low internal resistance offered by the cell is the reason e•m•f is always greater than P•d
*========================*
*_Advantages of connecting Lamps In parallel_*
1. The new across each lamp is the same .
2. Each lamp shines with the same brightness .
3. Each lamp can be turned on and off independently .
4. A family lamp does not cut off or break the supply of current to the other lamp .
E=Ivt
=I²Rt
=V²\R t
*_Conditions in which A piece of wire in A closed circuit may Not obey ohms Law_*
1. When the temperature of the wire is increased due to excessive heat.
2. When the wire is excessively bent in such a way that the molecular arrangement is distorted.
*=======================*
Simple Pendulum Experiment
Precautions✅
1. I ensured that the Bob was displaced through a small angle of displacement in order to
i) To maintain a uniform oscillation over a period of time
ii) In order to avoid damping effect i.e the influence between/upon on oscillating system that has the effect of restricting, preventing or retrieving its oscillations.
2. I ensured that I avoided conical oscillation or conical motion.
3. I ensured that I avoided parallax error of the meter rule.
4. I ensured I avoided zero error of the stop clock.(in order to avoid systematic error).
5. I ensured i took repeated readings in the timing in order to avoid random error.
6. I ensured that the windows were shut and the fans were off in order to avoid external air interference.
Amplitude → The maximum displacement a body undergoing S•H•M makes from its mean position or rest.
Period → This is the time taken for a body undergoing S•H•M to make one complete oscillation or revolution or cycle.
Frequency → This is the number of cycles or revolution made by a body undergoing S•H•M in one second.
(Hertz) or (Per second).
S•H•M is a to and fro type of motion or a periodic type of motion in which the acceleration is directly towards the center or fixed point and proportional to the displacement from that point.
E.g i Motion of string in musical instruments e.g Guitar
ii The motion of pendulum of a clock
iii The motion of pistons in a gasoline engine.
iv The motion of loaded test tubes oscillating vertically in water.
v The motion of a body suspended from a spiral spring.
*======================*
Light and Optics
(Focal length=15cm)
Precautions ✅
1. I avoided parallax error of meter rule when taking my readings
2. I ensured a co -linear arrangement of the objects, lens and screen or I ensured the optical components are aligned correctly.
3. I ensured that the lens was cleaned in order to obtain a clearer image.
4. I ensured that the lens was vertically placed in a lens holder.
5. I ensured that a sharp image was observed before taking my reading.
6. I ensured that the windows were closed using a curtain to obtain a sharp image and avoid external light interference.
Focal length of a lens is the distance between the optical center and the principal focus. It is 15cm if the focal length is 15cm.
*LU RD DITTO✅🥰*
*PHYSIC PRACTICAL DONE AND DUSTED*
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