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NECO 2019 Physics Practical Question and answer available now

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NECO 2019 Physics Practical Question and answer available now

     09 Jun 2019
NECO 2019 Practical Specimens (Agric,Biology,Physics,Chemistry)


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*NECO-PHYSICS-PRACTICALS-ANSWERS*

 ==========

 (1)
Centre of gravity C G = 50.0cm
Tabulate
Y(cm). |10|15|20|25|30|
K(cm). |31.2|33.5|36.0|38.2|40.6|
X(cm). |21.2|18.5|16.0|13.2|10.6|
K¹(cm). |27.0|29.7|33.0|35.5|38.4|
X¹(cm). |17.0|14.7|13.0|10.5|8.4|

 (1x)
Slope = increase in y-axis /increase in x-axis

 From the graph, 
Slope = (35-10)cm/(16-6)cm
Slope (s) = 35/10=2.5

 (1xi)
K =M1-Sm/S-1 
M1= 100g , Sm =50m , S =2.5

 K = 100-50/2.5-1 = 50/1.5
= 500/15=100/3
= 33.3g/cm

 Use any one

 (1ix)
GRAPH1: CLICK HERE FOR THE GRAPh1
(1ix)
Graph2:
CLICK HERE FOR THE GRAPH2

 (1xii)
(i)i avoided drought by closing the window
(ii)i avoided error due to parallax when reading the meter rule 

 (1bi)
couple is a pair of forces, equal in magnitude, oppositely directed, and displaced by perpendicular distance or moment. 

 (1bii)
CLICK HERE FOR THE IMAGE

Let the mass of beam = m
Taking moment about point C 5cm clockwise = sum of anitclockwise i;e moment
; 50*0.5=mx0.2
m=50*0.5/02=250/2=125g
Mass of the beam = 125g
==========
(3)
Tabulate
K,M,F 
E=3.0v
L(cm).|20|30|40|50|60|70|
I(A). |1.30|1.20|1.10|1.00|0.90|0.95|
X=E/I(V/A).
|2.31|2.50|2.73|3.00|3.33|3.16|

 (3)
CLICK HERE FOR THE GRAPH

 (3ix)
Slope = ΔL/Δx = 66-12/7-4 = 54/3=18cm/Ω
Intercept ,c (couldn't be shown on graph) 

 (3x)
Evaluating K =4.9 10^-7 S
K =4.9 × 10^-7 × 18
K=8.82 × 10^-6cm/Ω
(3xi)
- I ensured tight connections 
- I avoided error due to parallax on the ammeter 

 (3bi) 
- Keep the top or terminals clean 
- Do not tighten or removed cables while charging or discharging 
(3bii) Using ohms law, R = V/I=3.5/0.25
=14Ω
=========
Completed
=========
NECO PHYSICS PRACTICAL 


PHYSICS PRACTICAL

(1bi)
The principal of moments state
that if a body is in
equilibrium,then the sum of the
clockwise moments about any
point on the body is equal to the
sum of the anticlockwise
moments about the same point

(1bii)
Clockwise moment =Anti
clockwise moment
10×5 = RB × 7
RB= 10×5/7
RB=50/7
RB=7.14
RA + RB=10
RA+7.14 =10
RA=10 - 7.14 =2.86N


(1vii)

(PICK TWO)

(i)I ensured mass did not tourch/
rest on the table

(ii)I avoided error due to parallax
on metre rule

(iii)I noted zero error on metre
rule

(iv)I avoided draught

==============
==============


No2a........


2bi)  
A couple is a pair of forces, equal in magnitude, oppositely directed, and displaced by perpendicular distance or moment.

(2xiv) 
- I ensure both the object and the pin were in straight lines so as to avoid error due to parallax 
- I ensured that all the pins were vertically placed


=============
=============


(NUMBER 3)

(3bi)
Lost volt is the voltage lost due to
the internal resistance of a cell.
It is measured in volts

(3bii)
E= I(R+r)
4=I(2+0.5)
4=2.5I
I=4/2.5
I=1.6A



(3av) 
E=3.0v

(3avii) 
Tabulate

Under L(cm): 20.0; 30.0; 40.0; 50.0; 60.0; 70.0; 
Under I(A): 0.70; 0.60; 0.55; 0.50; 0.45; 0.40; 
Under X=E/I(Ohms): 4.2857; 5.0000; 5.4545; 6.0000; 6.6667; 7.5000; 

(3aix) 
slope = ΔL/ΔX = 66 - 12/7 - 4
= 54/3 = 18cm

Intercept, C


(3viii)
(Pick two)
(Precaution)

(i)I would ensure that the key is
opened when circuit is not in use
to avoid the cell being used up

(ii)I would ensure that the
electrical wires are tightly
connected

(iii)I would ensure clean
terminals
_________________________________
Q1.
determine the slope of the graph
and the intercept c
- evaluate k1 = k1 = 4π2/s and k2
=
(Xiii)- state any two of the
following precautions
- Avoided conical oscillations
- Ensured firm suspension of
pendulum
- Ensured reading is repeated
(shown on the table
- Avoided draught
-Corrected/noted for zero error
of metre rule/ stop match/clock
- Avoided parallax error in
reading metre rule/ stop clock

(b) (i) The period of oscillation of
a body is the time taken for the
body to make one complete to
and from movement

(ii) When a body is falling under
its weight (alone), the rate of
increase of its velocity with time
(as a result of the earth’s
gravitational pull) is the
acceleration of free fall due to gravity



(3ax) 
K = 4.9×10^-7
      K = 4.9×10^-7 × 18
      K = 8.82×10^-6cm/ohm

(3axi) 
-I ensured tight connections.
-I avoided error due to parallax on the ammeter. 

(3bi) 
keep the top or terminals clean. 
Do not tighten or remove cables while charging or discharging. 

(3bii) 
Using ohm's law
R = V/I = 3.5/0.25 = 14ohm
=======================================





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